How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?

The weight of the product is = 1.502g

Volume of cylcohexanone is = 2mL

Using NaBH

_{4}and methanol

**Moderators:** expert, ChenBeier, Xen

Hello everyone, kinda need help understanding on this topic.

How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?

The weight of the product is = 1.502g

Volume of cylcohexanone is = 2mL

Using NaBH_{4} and methanol

How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?

The weight of the product is = 1.502g

Volume of cylcohexanone is = 2mL

Using NaBH

- ChenBeier
- Distinguished Member
**Posts:**974**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

First develop the chemical reaction.

Then you can see how many mole of the keton correspond to the

Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

Then you can see how many mole of the keton correspond to the

Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

Okay thank you

So does the equation be something like this?

C

- ChenBeier
- Distinguished Member
**Posts:**974**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

Ohh i see its sodiumborate, thank you. But how do i convert 2ml to mole?

- ChenBeier
- Distinguished Member
**Posts:**974**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

First you need specific gravity δ = m/V, convert this to mass, then convert with molar mass to mole.

n =m/M

n =m/M